document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012875>Question 1012875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You were told by your teacher to makeva sketch of a rectangular garden such that is perimeter is at 19cm of the difference of length and width least 5m<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #629014 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=629014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "If you mean the difference between length and width <BR>\n" );
document.write( "is at least 5 cm (not 5 meters as you posted), then:<BR>\n" );
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document.write( "L=length; W=width<BR>\n" );
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document.write( "P=2(L+W)<BR>\n" );
document.write( "19=2(L+W)<BR>\n" );
document.write( "9.5=L+W<BR>\n" );
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document.write( "L-W=5<BR>\n" );
document.write( "L=5+W<BR>\n" );
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document.write( "9.5=L+W<BR>\n" );
document.write( "9.5=(5+W)+W<BR>\n" );
document.write( "4.5=2W<BR>\n" );
document.write( "2.25=W<BR>\n" );
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document.write( "L=W+5=2.25+5=7.75<BR>\n" );
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document.write( "ANSWER: One solution is a 7.75cm x 2.25 cm rectangle.<BR>\n" );
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