document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012873>Question 1012873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the volume of a cone is decreased by 20% and the height increased by 10%. How is the radius affected?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628964 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If the volume of a cone is decreased by 20% and the height increased by 10%. How is the radius affected? <BR>\n" );
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document.write( "Volume Formula: V = (1/3)pi*r^2*h<BR>\n" );
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document.write( "Modified:: 0.9V = (1/3)*pi*r^2*(1.1h)<BR>\n" );
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document.write( "Solve for \"r\"::<BR>\n" );
document.write( "r^2 = 2.7/[pi*1.1h]<BR>\n" );
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document.write( "r = sqrt[(2.7/1.1)*pi*h]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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