document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86860>Question 86860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok my problem is you have $30 in change in your drawer consisting of dimes and quarters write an inequality that shows the different number of coins in your drawer. so i think if I use x as the number of dimes and y as the quarters  can I write that f(y) >  f(x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62893 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> why can't you have 2 quarters and 295 dimes?\r<BR>\n" );
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document.write( "let c= # of coins, d= # of dimes, q= # of quarters\r<BR>\n" );
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document.write( "since $30 is evenly divisible by $.10, there must be an even number of quarters;<BR>\n" );
document.write( "that means at least 2 but no more than 118 so 2<=q<=118\r<BR>\n" );
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document.write( "2 quarters means 295 dimes; 118 quarters means 5 dimes ... so 5<=d<=295\r<BR>\n" );
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document.write( "the fewest coins is 123 (118q + 5d) and the most is 297 (2q + 295d) so 123<=c<=297 </SPAN>\n" );
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