document.write( "Question 1012801: Linda and Joanne sit 10 feet apart on a seesaw. If Linda weighs 80 lbs. and Joanne weighs 120 lbs., how far is the fulcrum from each girl. \n" ); document.write( "

Algebra.Com's Answer #628921 by MathTherapy(10556) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Linda and Joanne sit 10 feet apart on a seesaw. If Linda weighs 80 lbs. and Joanne weighs 120 lbs., how far is the fulcrum from each girl
\n" ); document.write( "

Let distance Linda is from the fulcrum be L
\n" );
document.write( "Then distance Joanne is from the fulcrum is: 10 - L
\n" );
document.write( "Since products of each weight and their distances from the fulcrum are equal, then we get: 80L = 120(10 – L)
\n" );
document.write( "80L = 1,200 – 120L
\n" );
document.write( "80L + 120L = 1,200
\n" );
document.write( "200L = 1.200
\n" );
document.write( "L, or distance Linda is from the fulcrum = , or  feet
\n" );
document.write( "Therefore, Joanne is 10 – 6, or  feet from the fulcrum\r
\n" );
document.write( "\n" );
document.write( "If the seesaw is balanced (not stated, but is assumed to be), Linda the lighter girl must be sitting farther
\n" );
document.write( "from the fulcrum than Joanne, whom, being the heavier of the 2, must be sitting closer to the fulcrum. \n" );
document.write( "

\n" );