document.write( "Question 1012821: $8000 was invested into 2 accounts yielding 3% and 3.5% interest. The total interest earned on the 2 accounts was $255. How much money was invested at 3%? \n" ); document.write( "
Algebra.Com's Answer #628908 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
- Total amount 8,000
\n" ); document.write( "- Of that, a certain amount was invested at 3%. We will call that amount x.
\n" ); document.write( "- The rest of the money, 8,000-x, was invested at 3.5%
\n" ); document.write( "------------------------------------------------------------
\n" ); document.write( "0.03x+0.035(8,000-x) = 255
\n" ); document.write( "0.03x+280-.035x = 255
\n" ); document.write( "-0.005x = -25
\n" ); document.write( "x = 5,000 this is how much was invested at 3%\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );