document.write( "Question 12363: Please help me I need this by Monday, please!! :0)\r
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document.write( "An investment of $1500 paid interest of $45 during a certain period. How much interest would an investment of $2000 invested at the same rate for the same length of time pay? \n" );
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Algebra.Com's Answer #6289 by rapaljer(4671) You can put this solution on YOUR website! Since the Interest paid is in proportion to the Investment, you can set up a proportion:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x = interest earned on a $2000 investment. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the same way, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An easier way to look at it, since $2000 is actually $1500 plus one third of that amount, the interest earned will be the corresponding $45 plus one third of that amount, or $45 + 15 = $60.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |