document.write( "Question 12363: Please help me I need this by Monday, please!! :0)\r
\n" ); document.write( "\n" ); document.write( "An investment of $1500 paid interest of $45 during a certain period. How much interest would an investment of $2000 invested at the same rate for the same length of time pay?
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Algebra.Com's Answer #6289 by rapaljer(4671)\"\" \"About 
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Since the Interest paid is in proportion to the Investment, you can set up a proportion:\r
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\n" ); document.write( "\n" ); document.write( "Let x = interest earned on a $2000 investment.
\n" ); document.write( "\"+%28Interest%29%2F+%28Investment%29\"= \"+45%2F1500+=+x%2F2000\"\r
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\n" ); document.write( "\n" ); document.write( "Remember \"a%2Fb=c%2Fd\" means \"ad=bc\"\r
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\n" ); document.write( "\n" ); document.write( "In the same way,
\n" ); document.write( "\"45%2F1500+=+x%2F2000+\" means \"45%2A2000=+x%2A1500\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=+%2845%2A2000%29%2F1500\"
\n" ); document.write( "\"x=+60+\"\r
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\n" ); document.write( "\n" ); document.write( "An easier way to look at it, since $2000 is actually $1500 plus one third of that amount, the interest earned will be the corresponding $45 plus one third of that amount, or $45 + 15 = $60.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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