document.write( "Question 1012731: 4 members of a family 10 years ago, the average age was 24 years old | 2 Children born after the family still has the same average age | Assuming that the child is under the age of 2 years, the difference | The current age of the children, find? \n" ); document.write( "
Algebra.Com's Answer #628876 by ankor@dixie-net.com(22740)\"\" \"About 
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4 members of a family 10 years ago, the average age was 24 years old
\n" ); document.write( "| 2 Children born after the family still has the same average age
\n" ); document.write( "| Assuming that the child is under the age of 2 years, the difference
\n" ); document.write( "| The current age of the children, find?
\n" ); document.write( ":
\n" ); document.write( "The present ages of the four original members of the family, a,b,c,d
\n" ); document.write( "The two children born later; e & f
\n" ); document.write( "Let f < 2 yrs, as it says
\n" ); document.write( "therefore
\n" ); document.write( "f = 1 yr old
\n" ); document.write( ":
\n" ); document.write( "Av 10 yrs ago
\n" ); document.write( "\"%28%28a-10%29+%2B+%28b-10%29+%2B+%28c-10%29+%2B+%28d-10%29%29%2F4+=+24\"
\n" ); document.write( "multiply both sides by 4, simplify
\n" ); document.write( "a + b + c + d - 40 = 96
\n" ); document.write( "a + b + c + d = 96 + 40
\n" ); document.write( "a + b + c + d = 136, their total age now
\n" ); document.write( ":
\n" ); document.write( "Therefore we can write the equation including the two late born children
\n" ); document.write( "\"%28136+%2B+e+%2B+f+%29%2F6\" = 24
\n" ); document.write( "multiply both sides by 6
\n" ); document.write( "136 + e + f = 144
\n" ); document.write( "e + f = 144 - 136
\n" ); document.write( "e + f = 8 yrs
\n" ); document.write( "we know that f is 1 yr old
\n" ); document.write( "e + 1 = 8
\n" ); document.write( "e = 7 yrs old
\n" ); document.write( ":
\n" ); document.write( "the difference: 6 yrs in the last two children
\n" ); document.write( "| The current age of the children, ages 7 and 1\r
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