document.write( "Question 1006953: A total of $2000 was invested: part at 8% and the rest at 12% per year. If after one year, both parts earned equal interest, how much was invested at each rate, and how much interest was earned in total?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #628860 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "E=amount at 8%; T=amount at 12% \n" ); document.write( ". \n" ); document.write( "E+T=2000 \n" ); document.write( "E=2000-T \n" ); document.write( ". \n" ); document.write( "0.08E=0.12T \n" ); document.write( "0.08(2000-T)=0.12T \n" ); document.write( "160-0.08T=0.12T \n" ); document.write( "160=0.20T \n" ); document.write( "800=T \n" ); document.write( "ANSWER 1: $800 was invested at 12%. \n" ); document.write( ". \n" ); document.write( "E=$2000-$800=$1200 \n" ); document.write( "ANSWER 2: $1200 was invested at 8%. \n" ); document.write( ". \n" ); document.write( "Total interest=0.08($1200)+0.12($800)=$96+$96=$192 \n" ); document.write( "ANSWER 3: Total interest was $192. \n" ); document.write( " \n" ); document.write( " |