document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012651>Question 1012651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the second of two numbers is 3 times the first. Eight times the sum of first number and -2 is equal to the second number decreased by 11. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628846 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the first and second numbers, x and y.  Then we can write<BR>\n" );
document.write( "y = 3x  and<BR>\n" );
document.write( "8(x - 2) = y - 11<BR>\n" );
document.write( "Now substitute the first eqn into the second and get<BR>\n" );
document.write( "8(x - 2) = 3x - 11<BR>\n" );
document.write( "8x - 16 = 3x - 11<BR>\n" );
document.write( "5x = 5<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "y = 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );