document.write( "Question 86889: 1.POPULATION\r
\n" ); document.write( "\n" ); document.write( "Suppose each person on the planet stood on a piece of ground that was 3 feet by 3 feet. What are the dimensions of the smallest square piece of land that could hold everyone on the planet? USE SENSIBLE UNITS!\r
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\n" ); document.write( "\n" ); document.write( "2. A large rubber ball was floating in a lake when the lake froze. The ball was carefully removed without breaking the ice, leaving a hole 3 feet 4 inches across and 8 inches deep. What was the radius of the ball? (Answer to the nearest 0.1 inches).\r
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\n" ); document.write( "\n" ); document.write( "3. You have 10 barrels of nails. Some of the barrels are full of nails that weigh 1 ounce. The others are full of nails that weigh 1.1 oz. How can you identify which barrels have which kind of nails while using a digital scale only ONE time?
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Algebra.Com's Answer #62884 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
1. world population is approx 6.6 billion ... 3 ft by 3 ft is a square yard, so 6.6 billion square yards\r
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\n" ); document.write( "\n" ); document.write( "1760yd=1mi ... 6,600,000,000/1760/1760=approx 2131sq mi ... this is a square approx 46.2 mi on a side\r
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\n" ); document.write( "\n" ); document.write( "2. If you picture a circular cross-section of the ball with a diameter going to the center of the bottom of the hole, a triangle formed by the edge of the hole and the ends of the diameter is a right triangle (inscribed in a semicircle).
\n" ); document.write( " Using the diameter (which is the hypotenuse) as the base of the triangle, the altitude is the radius of the hole (20 inches).
\n" ); document.write( " This altitude divides the hypotenuse such that the altitude is the geometric mean of the segments ... or 8:40::40:x ... so x=200 ... making the diameter 8+200 or 208 and the radius 104\r
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\n" ); document.write( "\n" ); document.write( "3. Take 1 nail from the first barrel, 2 from the next, 4 from the next, etc.; lastly taking 2^9 (512) nails from the 10th barrel\r
\n" ); document.write( "\n" ); document.write( "Weigh the nails and subtract 1023 (2^10-1) from the total\r
\n" ); document.write( "\n" ); document.write( "Multiply this number by 10 to avoid problems with the decimal point\r
\n" ); document.write( "\n" ); document.write( "Convert the resulting amount into binary (1's and 0's) and the barrels will be ordered starting with the rightmost (least significant) digit\r
\n" ); document.write( "\n" ); document.write( "The barrels with the heavier nails will be 1's and the lighter nails will be 0's
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