document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012753>Question 1012753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle is inserted in a 60° sector of a larger circle as shown above.  Price that the ratio of the radii of the circles is 1:3, and find the ratio of the areas of the circle and the sector.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628829 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well if the smaller circle has 1/3 the radius, its area is 1/9 as great.  The 60 degree sector is 1/6 of the larger circle.  So I'm thinking 1/9 to 1/6 is 2 to 3. </SPAN>\n" );
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