document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012742>Question 1012742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One solution is 80% acid and another one is 30% acid.  How much of each solution is needed to make a 150L solution that is 62% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628792 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 80% acid used, x.<BR>\n" );
document.write( "Then the amount of 30% acid used would be 150-x.<BR>\n" );
document.write( "The setup looks like this:<BR>\n" );
document.write( "(.80)x + (.30)(150-x) = (.62)(150)<BR>\n" );
document.write( "Now solve this for x...<BR>\n" );
document.write( ".8x + 45 - .3x = 93<BR>\n" );
document.write( ".5x = 48<BR>\n" );
document.write( "x = 96 L of 80% acid<BR>\n" );
document.write( "Then 150 - x = 54 L of 30% acid </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );