document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012695>Question 1012695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the following systems of equations algebraic ally and check :<BR>\n" );
document.write( "3x+y=3<BR>\n" );
document.write( "y=2x-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628697 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For this system, I would recommend the substitution method...<BR>\n" );
document.write( "3x+y=3<BR>\n" );
document.write( "y=2x-7<BR>\n" );
document.write( "Let's substitute the second equation into the first and get<BR>\n" );
document.write( "3x + (2x - 7) = 3<BR>\n" );
document.write( "5x - 7 = 3<BR>\n" );
document.write( "5x = 10<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "y = 2(2) - 7 = -3<BR>\n" );
document.write( "The answer is (2, -3).<BR>\n" );
document.write( "Checking the first equation gives<BR>\n" );
document.write( "3(2) + (-3) = 3<BR>\n" );
document.write( "6 - 3 = 3<BR>\n" );
document.write( "3 = 3 checks! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );