document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012689>Question 1012689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3.3\r<BR>\n" );
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document.write( "Evaluate the function f(x)=x^2 +6x+5 at the given values of the independent variable and simplify.\r<BR>\n" );
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document.write( "a. f(9)= \r<BR>\n" );
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document.write( "b. f(x+5)=\r<BR>\n" );
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document.write( "c. f(-x)= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628693 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For f(x) = x^2 + 6x + 5, we merely substitute the other values for x and evaluate, so that<BR>\n" );
document.write( "f(9) = 9^2 + 6(9) + 5 = 81 + 54 + 5 = 140<BR>\n" );
document.write( "f(x+5) = (x+5)^2 + 6(x+5) + 5 = x^2 + 10x + 25 + 6x + 30 + 5 = x^2 + 16x + 60<BR>\n" );
document.write( "f(-x) = (-x)^2 + 6(-x) + 5 = x^2 - 6x + 5 </SPAN>\n" );
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