document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012628>Question 1012628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do i write these as a single logarithm?\r<BR>\n" );
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document.write( "1) (log 3 - log 4) - log 2\r<BR>\n" );
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document.write( "2) log 2 + log 4 - log 7\r<BR>\n" );
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document.write( "and <BR>\n" );
document.write( "3) 1/2 log x + 1/3 log y - 2 log z </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628658 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Log (3/4)-log 2<BR>\n" );
document.write( "=Log 3/8=<BR>\n" );
document.write( "Check, the last log is -0.426<BR>\n" );
document.write( "0.477-0.602-0.301=-0.426<BR>\n" );
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document.write( "Log 8-log 7=<BR>\n" );
document.write( "log (8/7)<BR>\n" );
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document.write( "log {x^(1/2)y^(1/3)/z^2} </SPAN>\n" );
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