document.write( "Question 1012602: ABCD is a square of unit length. Points E and F are on the sides AB and AD respectively such that AE = AF = x.
\n" ); document.write( "Show that the area 'y' of the quadrilateral CDEF is given by y = 1/2 (1 + x - x^2). What is the quadrilaterals greatest possible area.
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Algebra.Com's Answer #628628 by rothauserc(4718)\"\" \"About 
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area of triangle EAF = x^2 / 2
\n" ); document.write( "area of triangle EBC = ((1-x)*1) / 2 = (1-x) / 2
\n" ); document.write( "area of square ABCD = 1 * 1 = 1
\n" ); document.write( "area of quadrilateral CDEF(y) = area of square ABCD - area of triangle EAF - area of triangle EBC
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\n" ); document.write( "y = 1 - x^2/2 - (1-x) / 2
\n" ); document.write( "y = (2 - x^2 - (1-x)) / 2
\n" ); document.write( "y = (1 +x -x^2) / 2
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\n" ); document.write( "this is a parabola that opens downward, so we want the value of x at the parabola's peak.
\n" ); document.write( "x = -b / 2a = (-1/2) / (2 * (-1/2)) = 1/2
\n" ); document.write( "now substitute 1/2 for x in the equation for y
\n" ); document.write( "y = (1 +(1/2) - (1/2)^2) / 2 = (5/4) / 2 = 5/8
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\n" ); document.write( "the greatest possible area for quadrilateral CDEF is 5/8
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\n" ); document.write( "here is the graph of the area of quadrilateral CDEF
\n" ); document.write( "\"graph%28300%2C+200%2C+-3%2C+3%2C+-3%2C+3%2C+%281+%2Bx+-x%5E2%29+%2F+2%29\"
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