document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012590>Question 1012590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have 3 to the sqrt of 21x. Which value of x makes the expression equivalent to 12 to the sqrt of 21? I don't remember how to work this. How does the number in front play in?? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628591 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm thinking you mean<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E%28sqrt%2821x%29%29+=+12%5E%28sqrt%2821%29%29 ALIGN=MIDDLE  ALT=\"3%5E%28sqrt%2821x%29%29+=+12%5E%28sqrt%2821%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If so, I think I would take the log of both sides and get<BR>\n" );
document.write( "sqrt(21x)*log3 = sqrt(21)*log12 <BR>\n" );
document.write( "sqrt(21x)*log3 = sqrt(21)*(log4 + log3)<BR>\n" );
document.write( "sqrt(x)*log3 = log4 + log3 <BR>\n" );
document.write( "sqrt(x) = (log4 + log3) / log3<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "x = [(log4 + log3) / log3]^2 = 5.116<BR>\n" );
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