document.write( "Question 994238: An investor has a total of $10,000 to deposit in two simple interest accounts. On one account, the annual simple interest rate is 7%. On the second account, the annual simple interest rate is 8%. How much should be invested in each account so that the total annual interest earned is $785? \n" ); document.write( "
Algebra.Com's Answer #628566 by macston(5194)\"\" \"About 
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\n" ); document.write( "S=amount at 7%; E=amount at 8%
\n" ); document.write( ".
\n" ); document.write( "S+E=$10000
\n" ); document.write( "E=$10000-S
\n" ); document.write( ".
\n" ); document.write( "0.07S+0.08E=$785
\n" ); document.write( "0.07S+0.08($10000-S)=$785
\n" ); document.write( "0.07S+$800-0.08S=$785
\n" ); document.write( "-0.01S=-$15
\n" ); document.write( "S=$1500
\n" ); document.write( "ANSWER 1: He should invest $1500 at 7%.
\n" ); document.write( ".
\n" ); document.write( "E=$10000-S
\n" ); document.write( "E=$10000-$1500
\n" ); document.write( "E=$8500
\n" ); document.write( "ANSWER 2: He should invest $8500 at 8%.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "0.07S+0.08E=$785
\n" ); document.write( "0.07($1500)+0.08($8500)=$785
\n" ); document.write( "$105+$680=$785
\n" ); document.write( "$785=$785
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