document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012573>Question 1012573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is 5.4 LTS of milk in a vessel. One third of the milk is used for some purpose. I. The remaining milk some water is added so that its volume increases by a factor of 1.25. One third of this new mixture is again used for some purpose. How much milk is left in the vessel now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628551 by </B><A HREF=/tutors/aboutme.mpl?userid=algebra+hello><B>algebra hello(55)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebra+hello><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> left milk=(1.25 5.4-5.4/3)-(1.25 5.4-5.4/3)/3<BR>\n" );
document.write( "=(1.25 3.6)-(1.25 3.6)/3<BR>\n" );
document.write( "=2*4.85/3<BR>\n" );
document.write( "=9.70/3<BR>\n" );
document.write( "=3.23 litre </SPAN>\n" );
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