document.write( "Question 1012550: find area of the triangle constructed by the lines5x+7y=35,4x+3y=12and x axis \n" ); document.write( "
Algebra.Com's Answer #628526 by macston(5194)\"\" \"About 
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\n" ); document.write( "Find vertices
\n" ); document.write( "Intersection of 5x+7y=35 (red on graph) and x-axis (purple on graph):
\n" ); document.write( "Set y=0, solve for x
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\n" ); document.write( "5x+7(0)=35
\n" ); document.write( "5x=35
\n" ); document.write( "x=7
\n" ); document.write( "One vertex is (7,0)(red crosses purple)
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\n" ); document.write( "Intersection of 4x+3y=12 (green on graph) and x axis (purple on graph):
\n" ); document.write( ".
\n" ); document.write( "4x+3(0)=12
\n" ); document.write( "4x=12
\n" ); document.write( "x=3
\n" ); document.write( "Second vertex at (3,0) (green crosses purple)
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\n" ); document.write( "The base is from (3,0)to (7,0)
\n" ); document.write( "Length of base is (7-3)=4
\n" ); document.write( "b=4
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\n" ); document.write( "5x+7y=35 . Multiply this by 3 (red on graph)
\n" ); document.write( "4x+3y=12 . Multiply this by 7 (green on graph)
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\n" ); document.write( "15x+21y=105
\n" ); document.write( "28x+21y=84 . Subtract second from first
\n" ); document.write( "-13x=21
\n" ); document.write( "x=-21/13
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\n" ); document.write( "5x+7y=35
\n" ); document.write( "5(-21/13)+7y=35
\n" ); document.write( "-105/13+7y=35
\n" ); document.write( "7y=455/13+105/13
\n" ); document.write( "7y=560/13
\n" ); document.write( "y=80/13
\n" ); document.write( "Third vertex is (-21/13,80/13) (red crosses green)
\n" ); document.write( "The height of the triangle is the y-value of this vertex.
\n" ); document.write( "h=80/13
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\n" ); document.write( "\"Area=%281%2F2%29bh\"
\n" ); document.write( "\"Area=%281%2F2%29%284%29%2880%2F13%29\"
\n" ); document.write( "\"Area=160%2F13\" square units
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