document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012536>Question 1012536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 9 am, mark and tom get on their motor bikes to meet each other from towns located 45 km apart. mark travels 5 km/h faster than tom. at what must each travel if they were to meet at 10:12 am? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628522 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In general, remember rate times time equals distance.<BR>\n" );
document.write( "Let us call Tom's rate, r.<BR>\n" );
document.write( "Then Mark's rate is r+5.<BR>\n" );
document.write( "The time they travel is an hour and twelve minutes...that's an hour and a fifth, or 6/5 hours.<BR>\n" );
document.write( "The total distance they cover is 45 km.<BR>\n" );
document.write( "Thus we can write<BR>\n" );
document.write( "(6/5)r + (6/5)(r+5) = 45<BR>\n" );
document.write( "Now solve this...maybe multiply everything by 5 to clear fractions...we get<BR>\n" );
document.write( "6r + 6(r+5) = 225<BR>\n" );
document.write( "6r + 6r + 30 = 225<BR>\n" );
document.write( "12r + 30 = 225<BR>\n" );
document.write( "12r = 195<BR>\n" );
document.write( "r = 195/12 = 16.25 km/h<BR>\n" );
document.write( "r+5 = 21.25 km/h </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );