document.write( "Question 1012536: at 9 am, mark and tom get on their motor bikes to meet each other from towns located 45 km apart. mark travels 5 km/h faster than tom. at what must each travel if they were to meet at 10:12 am? \n" ); document.write( "

Algebra.Com's Answer #628519 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "at 9 am, Mark and Tom get on their motor bikes to meet each other from towns located 45 km apart.
\n" ); document.write( "Mark travels 5 km/h faster than Tom. At what must each travel if they were to meet at 10:12 am?
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document.write( "Let x be Mark' speed in . Then tom' speed is x-5 \r\n" );
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document.write( "Since they move toward each other, the rate of decreasing the distance between them is x + (x-5) = 2x-5 .\r\n" );
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document.write( "The time they spent for their trip is 1 hour 12 minutes, or  of an hour.\r\n" );
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document.write( "Your equation is Time = ,   or\r\n" );
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document.write( " = .\r\n" );
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document.write( "To solve it, multiply both sides by 2x-5. You will get\r\n" );
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document.write( "6*(2x-5) = 5*45,   or\r\n" );
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document.write( "12x - 30 = 225,\r\n" );
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document.write( "12x = 225 + 30 = 255.\r\n" );
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document.write( "x =   = 21.25 .\r\n" );
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