document.write( "Question 1012550: find area of the triangle constructed by the lines5x+7y=35,4x+3y=12and x axis \n" ); document.write( "
Algebra.Com's Answer #628516 by Alan3354(69443)\"\" \"About 
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find area of the triangle constructed by the lines5x+7y=35,4x+3y=12and x axis
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\n" ); document.write( "Find the intersection of the 2 lines.\r
\n" ); document.write( "\n" ); document.write( "5x+7y=35
\n" ); document.write( "4x+3y=12
\n" ); document.write( "The y value of the intersection is 80/13
\n" ); document.write( "Since the other 2 vertices are on the x-axis, 80/13 is the height of the triangle.
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\n" ); document.write( "Find the intersections of the lines and the x-axis
\n" ); document.write( "5x + 7y = 35
\n" ); document.write( "@y = 0; x = 7
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\n" ); document.write( "4x + 3y = 12
\n" ); document.write( "@y = 0; x = 3
\n" ); document.write( "The base = 7-3 = 4
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\n" ); document.write( "Area = b*h/2 = (80/13)*4/2
\n" ); document.write( "Area = 160/13 sq units
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