document.write( "Question 1012550: find area of the triangle constructed by the lines5x+7y=35,4x+3y=12and x axis \n" ); document.write( "
Algebra.Com's Answer #628516 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! find area of the triangle constructed by the lines5x+7y=35,4x+3y=12and x axis \n" ); document.write( "----------- \n" ); document.write( "Find the intersection of the 2 lines.\r \n" ); document.write( "\n" ); document.write( "5x+7y=35 \n" ); document.write( "4x+3y=12 \n" ); document.write( "The y value of the intersection is 80/13 \n" ); document.write( "Since the other 2 vertices are on the x-axis, 80/13 is the height of the triangle. \n" ); document.write( "---- \n" ); document.write( "Find the intersections of the lines and the x-axis \n" ); document.write( "5x + 7y = 35 \n" ); document.write( "@y = 0; x = 7 \n" ); document.write( "----------- \n" ); document.write( "4x + 3y = 12 \n" ); document.write( "@y = 0; x = 3 \n" ); document.write( "The base = 7-3 = 4 \n" ); document.write( "---- \n" ); document.write( "Area = b*h/2 = (80/13)*4/2 \n" ); document.write( "Area = 160/13 sq units \n" ); document.write( " |