document.write( "Question 1012489: the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles. \n" ); document.write( "
Algebra.Com's Answer #628476 by MathTherapy(10555)\"\" \"About 
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the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.
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Let measure of vertex angle, be V
\n" ); document.write( "Then each congruent base angle = \"%281%2F2%29V\", or \"V%2F2\"
\n" ); document.write( "The angles of a triangle sum to \"180%5Eo\", and so, we get: \"V+%2B+2%28V%2F2%29+=+180\"
\n" ); document.write( "V + V = 180
\n" ); document.write( "2V = 180
\n" ); document.write( "V, or vertex angle measures: \"180%2F2\", or \"highlight_green%2890%5Eo%29\" \n" ); document.write( "
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