document.write( "Question 1012489: the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles. \n" ); document.write( "

Algebra.Com's Answer #628448 by ikleyn(52847) $\"\"$ $\"About$

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\n" ); document.write( "the vertex angle of an isosceles triangle is twice as large as one of the base angles. Find the measure of the vertex angles.
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document.write( "Answer. 90 degrees.\r\n" );
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document.write( "Solution\r\n" );
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document.write( "Let m be the measure of the angle at the base. Then the other angle at the base has the same measure m as the triangle is isosceles.\r\n" );
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document.write( "The vertex angle is 2m according to the condition.\r\n" );
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document.write( "Since the sum of interior angles of a triangle is 189 degrees, it gives you an equation\r\n" );
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document.write( "m + m + 2m = 180,   or  4m = 180.\r\n" );
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document.write( "Hence, m =  = 45 degrees for the angle at the base.\r\n" );
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document.write( "It gives 90 degrees for the vertex angle.\r\n" );
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document.write( "The problem is solved.\r\n" );
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