document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012224>Question 1012224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Regal Cinemas commissioned a national study to determine the amount of money spent on concessions by their customers. The study revealed that the amount spent follows a normal distribution with a mean of $6.11 and a standard deviation of $1.87.<BR>\n" );
document.write( "(a)	What proportion of all customers of Regal Cinemas spend more than $10.00 on concessions?\r<BR>\n" );
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document.write( "(b)	What percentage of all customers of Regal Cinemas spend between $5.00 and $10.00 on concessions on a typical outing at the movies?<BR>\n" );
document.write( "(c ) Determine the 90th percentile for money spent on concessions by Regal Cinemas customers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628366 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $6.11=mean<BR>\n" );
document.write( "$1.87=SD<BR>\n" );
document.write( "z>(10.00-6.11)/1.87=2.082<BR>\n" );
document.write( "Proportion is 0.0188<BR>\n" );
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document.write( "z for $5 is (5.00-6.11)/1.87=-0.5936<BR>\n" );
document.write( "probability of z between -0.5936 and 2.082 is 0.7048<BR>\n" );
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document.write( "90th percentile is z=1.282<BR>\n" );
document.write( "Multiply by 1.87=2.40 above the mean.<BR>\n" );
document.write( "$6.11+$2.40=$8.51<BR>\n" );
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