document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012430>Question 1012430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eli has a lot of loose change in his pocket, but only dimes and quarters. He counts his money and determines that he has $6.45. if he has 39 coins in total, how many of each does he have?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628359 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of dimes and quarters, d and q.  Then we have<BR>\n" );
document.write( "d + q = 39  and the value equation is<BR>\n" );
document.write( "10d + 25q = 645  (we work in cents)<BR>\n" );
document.write( "Now multiply the top one by 10 and subtract from the second...<BR>\n" );
document.write( "10d + 25q = 645<BR>\n" );
document.write( "-(10d + 10q = 390)<BR>\n" );
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document.write( "15q = 255<BR>\n" );
document.write( "q = 17 quarters<BR>\n" );
document.write( "and then we have <BR>\n" );
document.write( "d = 39 - q = 22 dimes </SPAN>\n" );
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