document.write( "Question 1012422: A tractor of mass 5*10^3kg is used to Low a car of mass 2.5*10^3kg. The tractor moved with a speed of 3.0m/sec just before the towing rope becomes taut. Calculate
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document.write( "(1) speed of the tractor immediately the rope become taut.
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document.write( "(2) loss in K. E of the system just after the car has started moving.
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document.write( "(3) impulse in the rope when it jerks the car into motion. \n" );
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Algebra.Com's Answer #628357 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Conservation of momentum. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Initially, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Impulse equals the momentum change of the car. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |