document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012429>Question 1012429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Nathan's lawnmower uses 2/3 of a tank of gas to cut three one-acre lawns.How many one-acre lawns can he cut with a full tank of gas?plz explain </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628356 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Nathan's lawnmower uses 2/3 of a tank of gas to cut three one-acre lawns.How many one-acre lawns can he cut with a full tank of gas?plz explain <BR>\n" );
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document.write( "Use a proportion::<BR>\n" );
document.write( "# of 1-acre lots/gas = # of 1-acre lots/gas<BR>\n" );
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document.write( "AL/1 = 3/(2/3)<BR>\n" );
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document.write( "AL = 3/(2/3) = 9/2 = 4.5 (# of 1-acre lots cut with 1 full tank)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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