document.write( "Question 1012418: john's age and mary's age sum up to 48. 60years later,john's age was double that of mary.
\n" ); document.write( "what are thier ages?
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Algebra.Com's Answer #628347 by fractalier(6550)\"\" \"About 
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Call John and Mary's age NOW, j and m. Then we have
\n" ); document.write( "j + m = 48, or j = 48 - m
\n" ); document.write( "Sixty years later,
\n" ); document.write( "j + 60 = 2(m + 60)
\n" ); document.write( "Now substitute in for j and get
\n" ); document.write( "48 - m + 60 = 2(m + 60)
\n" ); document.write( "108 - m = 2m + 120
\n" ); document.write( "This doesn't work...I think you meant six years later...
\n" ); document.write( "j + 6 = 2(m + 6)
\n" ); document.write( "48 - m + 6 = 2(m + 6)
\n" ); document.write( "54 - m = 2m + 12
\n" ); document.write( "42 = 3m
\n" ); document.write( "m = 14
\n" ); document.write( "j = 34
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