document.write( "Question 1012412: Make an equation of a line that passes through (2,-3) and is perpendicular to y=x-2 \n" ); document.write( "
Algebra.Com's Answer #628338 by macston(5194)\"\" \"About 
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slope-intercept form:
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=(1)x+(-2)
\n" ); document.write( "The slope is 1
\n" ); document.write( "The slope of the perpendicular line is the
\n" ); document.write( "negative inverse. Negative inverse of 1 is -1.
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\n" ); document.write( "The equation will have the form:
\n" ); document.write( "y=(-1)x+b
\n" ); document.write( "Put in values of given point and solve for b:
\n" ); document.write( "-3=(-1)(2)+b
\n" ); document.write( "-3=-2+b
\n" ); document.write( "-1=b
\n" ); document.write( "Use this value of b in the equation:
\n" ); document.write( "y=(-1)x+(-1)
\n" ); document.write( "y=-x-1
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\n" ); document.write( "ANSWER: Equation of the perpendicular line through (2,-3):
\n" ); document.write( "y=-x-1
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