document.write( "Question 1012412: Make an equation of a line that passes through (2,-3) and is perpendicular to y=x-2 \n" ); document.write( "
Algebra.Com's Answer #628338 by macston(5194)![]() ![]() You can put this solution on YOUR website! slope-intercept form: \n" ); document.write( "y=mx+b \n" ); document.write( "y=(1)x+(-2) \n" ); document.write( "The slope is 1 \n" ); document.write( "The slope of the perpendicular line is the \n" ); document.write( "negative inverse. Negative inverse of 1 is -1. \n" ); document.write( ". \n" ); document.write( "The equation will have the form: \n" ); document.write( "y=(-1)x+b \n" ); document.write( "Put in values of given point and solve for b: \n" ); document.write( "-3=(-1)(2)+b \n" ); document.write( "-3=-2+b \n" ); document.write( "-1=b \n" ); document.write( "Use this value of b in the equation: \n" ); document.write( "y=(-1)x+(-1) \n" ); document.write( "y=-x-1 \n" ); document.write( ". \n" ); document.write( "ANSWER: Equation of the perpendicular line through (2,-3): \n" ); document.write( "y=-x-1 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |