document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012412>Question 1012412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make an equation of a line that passes through (2,-3) and is perpendicular to y=x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628336 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the line you want is perpendicular to y = x - 2, its slope must be -1.<BR>\n" );
document.write( "Now plug into<BR>\n" );
document.write( "y = mx + b and get<BR>\n" );
document.write( "-3 = (-1)(2) + b<BR>\n" );
document.write( "-3 = -2 + b<BR>\n" );
document.write( "b = -1<BR>\n" );
document.write( "and your line must be<BR>\n" );
document.write( "y = -x - 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );