document.write( "Question 1012409: An airplane takes 5 hours to travel a distance of 4200km against the wind. The return trip takes 4 hours with the wind. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #628327 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "R=rate of plane; W=rate of wind \n" ); document.write( ". \n" ); document.write( "Against wind:(5 hours)(R-W)=4200km \n" ); document.write( "R-W=840 \n" ); document.write( "R=W+840 \n" ); document.write( ". \n" ); document.write( "With wind: (4 hours)(R+W)=4200km \n" ); document.write( "R+W=1050 \n" ); document.write( "(W+840)+W=1050 \n" ); document.write( "2W=210 \n" ); document.write( "W=105 \n" ); document.write( "ANSWER 1: Rate of wind = 105 km/hr. \n" ); document.write( ". \n" ); document.write( "R=W+840 \n" ); document.write( "R=105+840 \n" ); document.write( "R=945 \n" ); document.write( "ANSWER 2: Rate of plane in still air = 945 km/hr. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "(5 hours)(R-W)=4200 \n" ); document.write( "(5hrs)(945-105)=4200 \n" ); document.write( "(5hrs)(840)=4200 \n" ); document.write( "4200=4200 \n" ); document.write( ". \n" ); document.write( "(4 hrs)(R+W)=4200 \n" ); document.write( "(4 hrs)(945+105)=4200 \n" ); document.write( "(4 hrs)(1050)=4200 \n" ); document.write( "4200=4200 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |