document.write( "Question 1012409: An airplane takes 5 hours to travel a distance of 4200km against the wind. The return trip takes 4 hours with the wind. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #628327 by macston(5194)\"\" \"About 
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\n" ); document.write( "R=rate of plane; W=rate of wind
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\n" ); document.write( "Against wind:(5 hours)(R-W)=4200km
\n" ); document.write( "R-W=840
\n" ); document.write( "R=W+840
\n" ); document.write( ".
\n" ); document.write( "With wind: (4 hours)(R+W)=4200km
\n" ); document.write( "R+W=1050
\n" ); document.write( "(W+840)+W=1050
\n" ); document.write( "2W=210
\n" ); document.write( "W=105
\n" ); document.write( "ANSWER 1: Rate of wind = 105 km/hr.
\n" ); document.write( ".
\n" ); document.write( "R=W+840
\n" ); document.write( "R=105+840
\n" ); document.write( "R=945
\n" ); document.write( "ANSWER 2: Rate of plane in still air = 945 km/hr.
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\n" ); document.write( "CHECK:
\n" ); document.write( "(5 hours)(R-W)=4200
\n" ); document.write( "(5hrs)(945-105)=4200
\n" ); document.write( "(5hrs)(840)=4200
\n" ); document.write( "4200=4200
\n" ); document.write( ".
\n" ); document.write( "(4 hrs)(R+W)=4200
\n" ); document.write( "(4 hrs)(945+105)=4200
\n" ); document.write( "(4 hrs)(1050)=4200
\n" ); document.write( "4200=4200
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