document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012389>Question 1012389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An 8-inch By 10-inch Photo Is Being Reduced Proportionally. The 10-inch Side Is Reduced By X Inches. What Is The CHANGE In The Area In Terms Of X? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628290 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An 8-inch By 10-inch Photo Is Being Reduced Proportionally. The 10-inch Side Is Reduced By X Inches. What Is The CHANGE In The Area In Terms Of X?<BR>\n" );
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document.write( "New area = (10 - x)*(8 - 0.8x) = 0.8x^2 - 10.8x + 80 sq inches<BR>\n" );
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document.write( "Change = 80 - (0.8x^2 - 10.8x + 80)<BR>\n" );
document.write( "= 10.8x - 0.8x^2 </SPAN>\n" );
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