document.write( "Question 1012333: Prove the identity sin(pi/2-x) cot(pi/2+x)= -sinx \n" ); document.write( "
Algebra.Com's Answer #628222 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"+sin%28pi%2F2-x%29+cot%28pi%2F2%2Bx%29=+-sin%28x%29+\"\r
\n" ); document.write( "\n" ); document.write( "using Cofunctions Identities, we have:
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\n" ); document.write( "\"sin%28pi%2F2-x%29+=cos%28x%29\" and\r
\n" ); document.write( "\n" ); document.write( "\"cot%28pi%2F2%2Bx%29=-tan%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "so, \"cos%28x%29+%28-tan%28x%29%29=+-sin%28x%29\" ...since \"-tan%28x%29=-sin%28x%29%2Fcos%28x%29\", we have\r
\n" ); document.write( "\n" ); document.write( "\"cos%28x%29+%28-sin%28x%29%2Fcos%28x%29%29=+-sin%28x+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28cos%28x%29+%29%28-sin%28x%29%2Fcross%28cos%28x%29%29%29=+-sin%28x%29\" \r
\n" ); document.write( "\n" ); document.write( "\"-sin%28x%29=+-sin%28x%29+\"\r
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