document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86861>Question 86861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x) = xsquared - x - 2 if f = 0,-2,1 I think i have to put the o and -2 and 1 where the x is and then do the equation but when I have a -2 and i subsitute  it where their is a minus x then do I add the 2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62821 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you get caught up in all the sign changes, I advise to use paranthesis.<BR>\n" );
document.write( "f(x) = x^2 - x - 2<BR>\n" );
document.write( "f(x) = (x)^2 - (x) - 2<BR>\n" );
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document.write( "If: f(x) = 0,-2,1<BR>\n" );
document.write( "0 = (x)^2 - (x) - 2<BR>\n" );
document.write( "-2 = (x)^2 - (x) - 2<BR>\n" );
document.write( "1 = (x)^2 - (x) - 2<BR>\n" );
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document.write( "If: x = 0,-2,1<BR>\n" );
document.write( "f(0) = (0)^2 - (0) - 2 = -2<BR>\n" );
document.write( "f(-2) = (-2)^2 - (-2) - 2 = 4 + 4 - 2 = 6<BR>\n" );
document.write( "f(1) = (1)^2 - (1) - 2 = 1 - 1 - 2 = -2 </SPAN>\n" );
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