document.write( "Question 1012225: 3. The first AUM baseball player coming to bat in an inning gets a hit 25% of the time. The second player coming to bat in an inning gets a hit 32% of the time. Consider their at-bats together, assuming that the outcomes of these two at-bats are independent of each other. What is the probability that neither of them gets a hit? \n" ); document.write( "
Algebra.Com's Answer #628184 by Theo(13342)\"\" \"About 
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first player gets a hit 25% of the time.
\n" ); document.write( "this means he doesn't get a hit 75% of the time.\r
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\n" ); document.write( "\n" ); document.write( "second player gets a hit 32% of the time.
\n" ); document.write( "this means he doesn't get a hit 68% of the time.\r
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\n" ); document.write( "\n" ); document.write( ".75 * .68 = .51.\r
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\n" ); document.write( "\n" ); document.write( "neither will get a hit 51% of the time.\r
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\n" ); document.write( "\n" ); document.write( "the total probabilities are:\r
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\n" ); document.write( "\n" ); document.write( "both get a hit = .25 * .32 = .08
\n" ); document.write( "first gets a hit and second doesn't = .25 * .68 = .17
\n" ); document.write( "first doesn't get a hit and second does = .75 * .32 = .24
\n" ); document.write( "both gon't get a hit = .75 * .68 = .51\r
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\n" ); document.write( "\n" ); document.write( "add up all the probabilities and you should get 1.
\n" ); document.write( ".08 + .17 + .24 + .51 = 1\r
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