document.write( "Question 1012285: Liz is 2.5 times her sons present age. Eight years ago, the total of their ages was 47. How old is each person now? \n" ); document.write( "

Algebra.Com's Answer #628166 by macston(5194) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "S=son's age; L=Liz's age=2.5S
\n" ); document.write( ".
\n" ); document.write( "(S-8)+(L-8)=47
\n" ); document.write( "S+L-16=47
\n" ); document.write( "S+L=63
\n" ); document.write( "The sum of their ages now is 63.
\n" ); document.write( ".
\n" ); document.write( "S+L=63
\n" ); document.write( "S+2.5S=63
\n" ); document.write( "3.5S=63
\n" ); document.write( "S=18
\n" ); document.write( "ANSWER 1: Son is 18 years old.
\n" ); document.write( ".
\n" ); document.write( "L=2.5S=2.5(18)=45
\n" ); document.write( "Liz is 45 years old.
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "(S-8)+(L-8)=47
\n" ); document.write( "(18-8)+45-8)=47
\n" ); document.write( "10+37=47
\n" ); document.write( "47=47
\n" ); document.write( " \n" ); document.write( "

\n" );