document.write( "Question 1012198: A searchlight has a parabolic reflector that forms a “bowl” which is 12 inches wide from rim to rim and 8 inches deep. If the filament of the light bulb is located at the focus, how far from the vertex of the reflector is it? \n" ); document.write( "
Algebra.Com's Answer #628092 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the factor, a. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "The equation for the parabola more specifically can be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What about the focus? \n" ); document.write( "Put the equation with the p into the same form as the more specific-found equation. The value of p is THE DISTANCE FROM VERTEX TO FOCUS. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Comparing the corresponding equation parts, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The focus will be on the \"opening upward\" side of the parabola, as described in this discussion, above the origin, so the focus is |