document.write( "Question 1012192: Mr. Charles bought a total of 5 pounds of fruit. He spent $6.58 and he bought apples, oranges, and grapes. How much of each fruit did Mr. Charles buy?\r
\n" ); document.write( "\n" ); document.write( "Apples cost $0.95/pound
\n" ); document.write( "Oranges cost $0.83/pound
\n" ); document.write( "grapes cost 1.60/pound\r
\n" ); document.write( "\n" ); document.write( "Thank you for your consideration of assistance.
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Algebra.Com's Answer #628089 by macston(5194)\"\" \"About 
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\n" ); document.write( "A=pounds of apples; R=pounds of oranges; G=pounds of grapes
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\n" ); document.write( "The problem indicates he bought all three, so he must
\n" ); document.write( "have bought at least 1 pound of each:
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\n" ); document.write( "$0.95+$0.83+$1.60=$3.38
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\n" ); document.write( "He has bought 3 pounds and spent $3.38, so he has
\n" ); document.write( "2 more pounds to buy and ($6.58-$3.38=) $3.20 to spend.
\n" ); document.write( "The only combination of two pounds that adds up to $3.20
\n" ); document.write( "is two ponds of grapes.
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\n" ); document.write( "ANSWER: Mr. Charles bought one pound of apples,
\n" ); document.write( "one pound of oranges, and three pounds of grapes.
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\n" ); document.write( "CHECK:
\n" ); document.write( "$0.95A+$0.83R+$1.60G=$6.58
\n" ); document.write( "$0.95(1)+$0.83(1)+&1.60(3)=$6.58
\n" ); document.write( "$0.95+$0.83+$4.80=$6.58
\n" ); document.write( "$6.58=$6.58
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