document.write( "Question 1012205: Jerry is a years older than his brother. In 5 years, Jerry will be twice is old as his brother. Find their ages now? \n" ); document.write( "
Algebra.Com's Answer #628079 by macston(5194)![]() ![]() You can put this solution on YOUR website! a=years older Jerry is than his brother \n" ); document.write( ". \n" ); document.write( "B=brother's age; J=Jerry's age=B+a \n" ); document.write( ". \n" ); document.write( "J+5=2(B+5) \n" ); document.write( "B+a+5=2B+10 \n" ); document.write( "a-5=B \n" ); document.write( "ANSWER 1: Brother is (a-5) years old. \n" ); document.write( ". \n" ); document.write( "J=B+a=(a-5)+a=2a-5 \n" ); document.write( "ANSWER 2: Jerry is 2a-5 years old.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |