document.write( "Question 86811: Simplify:\r
\n" ); document.write( "\n" ); document.write( "square root of 500
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Algebra.Com's Answer #62806 by bucky(2189)\"\" \"About 
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Since 500 is an even number you know that it is divisible by 2. Therefore, you can write
\n" ); document.write( "it as \"500+=+250+%2A+2\"
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\n" ); document.write( "But 250 is also even and divisible by 2. So 250 can be replaced by 125 * 2. Therefore,
\n" ); document.write( "you can replace 500 by 125*2*2 which is equivalent to \"500+=+125%2A2%5E2\"
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\n" ); document.write( "Then \"125+=+5%2A5%2A5+=+5%2A5%5E2\". So if you substitute \"5%2A5%5E2\" for 125 you get:
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\n" ); document.write( "\"500+=+5%2A5%5E2%2A2%5E2\"
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\n" ); document.write( "Taking the square root of all three terms in this multiplication string results in:
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\n" ); document.write( "So the simplified form of \"sqrt%28500%29\" is \"10%2Asqrt%285%29\"
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\n" ); document.write( "Had you recognized it earlier, you could have written:
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\n" ); document.write( "\"sqrt%28500%29+=+sqrt%28100%2A5%29+=+sqrt%28100%29%2Asqrt%285%29+=+10%2Asqrt%285%29\"
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\n" ); document.write( "much quicker, but not as much practice as the long way.
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\n" ); document.write( "Hope this helps you to see how square root problems such as this one can be simplified.
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