document.write( "Question 1012164: what is the vertex directrix and focus of the equation (x+5)^2=4y \n" ); document.write( "
Algebra.Com's Answer #628018 by MathLover1(20849)\"\" \"About 
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\"%28x%2B5%29%5E2=4y+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29%28x%2B5%29%5E2+\"....compare to \"y=%28x-h%29%5E2%2Bk\" and you see that \"h=-5\" and \"k=0\"\r
\n" ); document.write( "\n" ); document.write( "so, vertex is at (\"-5\",\"0\"\r
\n" ); document.write( "\n" ); document.write( "or, we can use standard form and calculate coordinates of the vertex like this:\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29%28x%5E2%2B10x%2B25%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29x%5E2%2B%281%2F4%2910x%2B%281%2F4%2925+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29x%5E2%2B%285%2F2%29x%2B%2825%2F4%29+\"\r
\n" ); document.write( "\n" ); document.write( "the x-coordinate of the focus is:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+-b+%2F%282a%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+-%285%2F2%29%2F+%282%281%2F4%29%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+-%285%2F2%29%2F+%281%2F2%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+-%2810%2F2%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x+=+-5\" \r
\n" ); document.write( "\n" ); document.write( "then, y-coordinate is\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%29%28-5%29%5E2%2B%285%2F2%29%28-5%29%2B%2825%2F4%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F4%2925-%2825%2F2%29%2B%2825%2F4%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=25%2F4-50%2F4%2B%2825%2F4%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=50%2F4-50%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=0+\"\r
\n" ); document.write( "\n" ); document.write( "so, we got same result for vertex\r
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\n" ); document.write( "\n" ); document.write( "the focus is:\r
\n" ); document.write( "\n" ); document.write( "The focus lies on the axis of symmetry of the parabola, and has the y-coordinate \"k%2B1%2F%284a%29\". Because we just found the vertex to be (\"-5\",\"0\"), we know the axis of symmetry to be \"x=-5\", and the focus lies on that line.\r
\n" ); document.write( "\n" ); document.write( "y-coordinate is at \"1%2F%284a%29+=1%2F%284%281%2F4%29%29=1%2F%284%2F4%29=1\"\r
\n" ); document.write( "\n" ); document.write( "and the coordinates of the focus are:(\"-5\",\"1\")\r
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\n" ); document.write( "\n" ); document.write( "Once you know the y=coordinate of the vertex, \"k=0\", it is given by \"y+=+k+%96+p\", where \"p+=+1%2F%284a%29\". Thus, as we calculated for the focus, above:\r
\n" ); document.write( "\n" ); document.write( "\"p+=+1%2F%284a%29+=+1%2F%284%2A%281%2F4%29%29+=+1\"\r
\n" ); document.write( "\n" ); document.write( "and the directrix is \"y+=+0+%96+1+=-1\"\r
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