document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012148>Question 1012148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the trig identity used to obtain the expression (cscx-1)(1+cscx)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #628005 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=628005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The product is csc^2 (x)-1<BR>\n" );
document.write( "That is (1/sin^2(x)) -1<BR>\n" );
document.write( "putting everything over sin^2 (x)<BR>\n" );
document.write( "(1-sin^2 (x))/sin^2 (x)<BR>\n" );
document.write( "But 1-sin^2 (x)=cos^2 (x)<BR>\n" );
document.write( "Therefore, the identity is cos^2 (x)/sin^2 (x)<BR>\n" );
document.write( "That is cot ^2 (x) </SPAN>\n" );
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