document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1012144>Question 1012144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Without using calculator or tables ,find the value of log3.6 given that log2 equer to 0.3010,log3 equer to 0.4771 and log5 equer to 0.6990 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #627998 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=627998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way is log 2+log 3=log 6<BR>\n" );
document.write( "log 6=0.7781<BR>\n" );
document.write( "log 36=2log 6=1.5562<BR>\n" );
document.write( "log 3.6=log (36)/log (10)=log 36 - log 10=1.5562-1=0.5562 </SPAN>\n" );
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