document.write( "Question 86809: x^3- 3x^2-4x+12=0\r
\n" ); document.write( "\n" ); document.write( "i have to solve for x
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Algebra.Com's Answer #62798 by checkley75(3666)\"\" \"About 
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x^3-3x^2-4x+12=0
\n" ); document.write( "x^2(x-3)-4(x-3)=0
\n" ); document.write( "(x^2-4)(x-3)=0
\n" ); document.write( "(x+2)(x-2)(x-3)=0
\n" ); document.write( "x+2=0
\n" ); document.write( "x=-2 answer.
\n" ); document.write( "x-2=0
\n" ); document.write( "x=2 answer.
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3 answer.
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