document.write( "Question 1012127: Good evening (Happy New Year to you all!!)
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document.write( "Has somebody the patience to explain me step by step the solution of
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document.write( "this exp.equation:? 4^(x-3)+2^(13-2x)=24
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document.write( "Results should be: x=9/2 or x=5
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document.write( "Thank you very much in advance
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Algebra.Com's Answer #627977 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 4^(x-3)+2^(13-2x)=24 \n" ); document.write( "4 = 2^2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Sub u for 2^2x \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( "2x = 10 \n" ); document.write( "x = 5 \n" ); document.write( "-------------------------- \n" ); document.write( " \n" ); document.write( "x = 9/2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |