document.write( "Question 1012127: Good evening (Happy New Year to you all!!)
\n" ); document.write( "Has somebody the patience to explain me step by step the solution of
\n" ); document.write( "this exp.equation:? 4^(x-3)+2^(13-2x)=24
\n" ); document.write( "Results should be: x=9/2 or x=5
\n" ); document.write( "Thank you very much in advance
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Algebra.Com's Answer #627977 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
4^(x-3)+2^(13-2x)=24
\n" ); document.write( "4 = 2^2
\n" ); document.write( "\"2%5E%282x-6%29+%2B+2%5E%2813-2x%29+=+24\"
\n" ); document.write( "\"2%5E%282x%29%2F2%5E6+%2B+2%5E13%2F%282%5E%282x%29%29+=+24\"
\n" ); document.write( "\"2%5E%282x%29%2A2%5E%282x%29+%2B+2%5E13%2A2%5E6+=+24%2A2%5E6%2A2%5E%282x%29\"
\n" ); document.write( "\"2%5E%284x%29+-+24%2A64%2A2%5E%282x%29+%2B+2%5E19+=+0\"
\n" ); document.write( "Sub u for 2^2x
\n" ); document.write( "\"u%5E2+-+1536u+%2B+2%5E19+=+0\"
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-1536x%2B524288+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1536%29%5E2-4%2A1%2A524288=262144\".
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\n" ); document.write( " Discriminant d=262144 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1536%2B-sqrt%28+262144+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%28-1536%29%2Bsqrt%28+262144+%29%29%2F2%5C1+=+1024\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-1536%29-sqrt%28+262144+%29%29%2F2%5C1+=+512\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"1x%5E2%2B-1536x%2B524288\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-1536x%2B524288+=+%28x-1024%29%2A%28x-512%29\"
\n" ); document.write( " Again, the answer is: 1024, 512.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1536%2Ax%2B524288+%29\"

\n" ); document.write( "\n" ); document.write( "=================
\n" ); document.write( "\"2%5E%282x%29+=+1024+=+2%5E10\"
\n" ); document.write( "2x = 10
\n" ); document.write( "x = 5
\n" ); document.write( "--------------------------
\n" ); document.write( "\"2%5E%282x%29+=+512+=+2%5E9\"
\n" ); document.write( "x = 9/2\r
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