document.write( "Question 1012117: Please help me solve this qeuation : 3x²-11x+6 ≤ 0 \n" ); document.write( "
Algebra.Com's Answer #627972 by Theo(13342)\"\" \"About 
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3x^2 - 11x + 6 <= 0\r
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\n" ); document.write( "\n" ); document.write( "set the equation equal to 0 to get:\r
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\n" ); document.write( "\n" ); document.write( "3x^2 - 11x + 6 = 0\r
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\n" ); document.write( "\n" ); document.write( "factor to get (3x-2) * (x-3) = 0\r
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\n" ); document.write( "\n" ); document.write( "set each of the factors equal to 0 and solve for x to get x = 2/3 and x = 3.\r
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\n" ); document.write( "\n" ); document.write( "you have 2 checkpoints and 3 intervals to check.\r
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\n" ); document.write( "\n" ); document.write( "first interval is x < 2/3.
\n" ); document.write( "second interval is x > 2/3 and < 3.
\n" ); document.write( "third interval is x > 3\r
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\n" ); document.write( "\n" ); document.write( "just pick values in those intervals and determine whether they are positive or negative.\r
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\n" ); document.write( "\n" ); document.write( "you will find that y is positive when x < 2/3 and y is negative when x < 2/3 and < 3 and y is positive when x > 3.\r
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\n" ); document.write( "\n" ); document.write( "the original equation says that 3x^2 - 11x + 6 <= 0.\r
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\n" ); document.write( "\n" ); document.write( "that occurs in the interval where x >= 2/3 and <= 3.\r
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\n" ); document.write( "\n" ); document.write( "your solution is 2/3 <= x <= 3.\r
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\n" ); document.write( "\n" ); document.write( "here's a graph of the equation.\r
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\n" ); document.write( "\n" ); document.write( "you can see the interval where the equation is less than or equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "it is between x = 2/3 and x = 3, including x = 2/3 and x = 3.\r
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