document.write( "Question 1012110: Two consecutive numbers are such that three times the smaller one added to twice the bigger one is 27. Find the number? \n" ); document.write( "

Algebra.Com's Answer #627968 by ValorousDawn(53) $\"\"$ $\"About$

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Lets say the bigger number is y, and the smaller number is x. If they're consecutive, then y=x+1.
\n" ); document.write( "Three times the smaller one is 3x, added to twice to the bigger one is 2y. They add to 27, to get the equation $\"3x%2B2y=27\"$
\n" ); document.write( "We use substitution y=x+1 to get $\"3x%2B2%28x%2B1%29=27\"$ and solve.
\n" ); document.write( " $\"3x%2B2x%2B2=27\"$
\n" ); document.write( " $\"5x=25\"$
\n" ); document.write( " $\"x=5%7D%7D%0D%0A%7B%7B%7By=%285%29%2B1\"$
\n" ); document.write( " $\"y=6\"$ \n" ); document.write( "

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