document.write( "Question 86798This question is from textbook
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document.write( ": A train goes a distance of 120 miles at a certain speed. If the train had gone 10mph faster it would have arrived 2 hours earlier. How fast is the train going? \n" );
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Algebra.Com's Answer #62796 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A train goes a distance of 120 miles at a certain speed. If the train had gone 10mph faster it would have arrived 2 hours earlier. How fast is the train going? \n" ); document.write( ": \n" ); document.write( "Let s = actual speed of the train \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = Distance/speed \n" ); document.write( ": \n" ); document.write( "Actual time = Faster speed time + 2 hrs \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "multiply equation by s(s+10) \n" ); document.write( "120(s+10) = 120s + 2(s(s+10)) \n" ); document.write( "120s + 1200 = 120s + 2s^2 + 20s \n" ); document.write( "120s + 1200 = 2s^2 + 140s \n" ); document.write( "0 = 2s^2 + 140s - 120s - 1200 \n" ); document.write( "2s^2 + 20s - 1200 = 0; a quadratic equation \n" ); document.write( "Simplify divide by 2: \n" ); document.write( "s^2 + 10s - 600 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(s+30)(s-20) = 0 \n" ); document.write( "s = 20 mph \n" ); document.write( ": \n" ); document.write( "Check solution Using time: \n" ); document.write( "120/20 = 6 hrs \n" ); document.write( "120/30 = 4 hrs; 2hrs less \n" ); document.write( " \n" ); document.write( " |